-x^2+45x-350=0

Solution for -x^2+45x-350=0 equation:

-x^2+45x-350=0

We add all the numbers together, and all the variables

-1x^2+45x-350=0

a = -1; b = 45; c = -350;
Δ = b2-4ac
Δ = 452-4·(-1)·(-350)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-25}{2*-1}=\frac{-70}{-2}
=+35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+25}{2*-1}=\frac{-20}{-2}
=+10
$